Correct answer: Rc:e51...Qh1/Qg2/Qf2/Qe2[a]/Q:d2/[б]//Qg1/Rf4 2.Q:e5#[A] 1...Re4[c] 2.Rd3#[Б] 1.Re:e5? (2.Be3#/Bc3#) 1...Qe2[a] 2.Re3
