Correct answer: Nc51...N:e4[a] 2.Be5#[A] 1...R:e4/[б]/ 2.Ba7#[Б] 1.Ng5? (2.R:d5#) 1...N:e4[a] 2.Ne6#[C] 1...R:e4/[б]/ 2.Nf3#[D] but 1...Ne3[c]! 1.