Correct answer: Qe31...Be4[a] 2.Qf7#[A] 1...Qe7/Qg1/Qf2/Qd2/Q:c3/[б]/ 2.N:e7#[C] 1...Nc4/Nc8[c]/N:d7/Na4/Na8 2.Q:c4#[D] 1...Bh4[d]/B
