Correct answer: Qb41...Ne6[a]/Nf7/Nc6/[б]//Nb7 2.Q:e6#[A] 1...Be5[c]/Ba7[d] 2.Q:e5#[C] 1...Bc4[e] 2.Q:h1#[D] 1...Bd6 2.Ngf6#/Nhf6#[Б] 1.Qe3?