Correct answer: Ne51...Bg4[a] 2.Qe5#[A] 1...Ne4/[б]//Nb7/[б]//Na4/[б]//Na6/[б]/ 2.R:e4#[Б] 1...Ne6[c] 2.Rf5#[C] 1...N:d2+ 2.B:d2# 1...Bc7/Ba7 2.B