Correct answer: Be51...Be8[a]/Bc6/[б]/ 2.Re4#[A] 1...B:a4[c] 2.Re5#[Б] 1...Qh2[d]/Qh1[e]/Q:h4[f]/Qg2[e]/Qf1[e] 2.Ne5#[C] 1...B:e6+ 2.Q:e6# 1...B
