Correct answer: Qh51...e3[a] 2.Bc2#[A] 1...c:d4/[б]//c4[c] 2.d6#[Б] 1...Ne6/Nc6/Nb7 2.R:f7# 1...Bg2/Bf1 2.g4# 1.R:c5[C]? (2.d6#[Б]) 1...e3[a] 2.Bc2#[A] 1...Ne6
