Correct answer: 1. Nd41.Nd6? (2.f8N#[A]) 1...Bd4[a] 2.Qf5#[Б] 1...B:d6/[б]/ 2.Rg1#[C] but 1...Ba2! 1.Nd4! (2.Rg1#[C]) 1...B:d4[a] 2.f8N#[A]
