Correct answer: Nd51...Rd5[a]/Be4 2.Qe4#[A] 1...Bd5/[б]/ 2.Nb5#[Б] 1...Rh4/Rh3/Rh2/Rh1/Rh6/Rh7/Rh8/Re5/f5 2.Qe5# 1.Kb2? (2.Rd1#[C
