Correct answer: Qc71...Bd6[a] 2.Qa2#[Б] 1...Bd4/Be3/Bf2/Bg1/Bf8/Bb6/Ba7/d6/[б]/ 2.Nf8#[A] 1...Kf7 2.Nf4#/Nf8#[A] 1.Qb8? (2.Nf4#) 1.