Correct answer: Nd41...Nh5[a]/Ne6/[б]//Ne8[c] 2.Qe6#[A] 1...Nb3[d]/Nc2[e] 2.Q:b3#[Б] 1.Ka3? zz 1...Nh5[a]/Ne6/[б]//Ne8[c] 2.Qe6#[A] 1...Nb3[d]