Correct answer: Qf11...Bc4[a]/Bd3[a]/Be2[a]/Bf1[a] 2.B:c4#[A]/Qb6#[Б] 1...Bd7/[б]//Be8[c] 2.Qb6#[Б] 1...Ba4 2.b4#/Qb6#[Б] 1...Ba6 2.Qb6#[Б]/Qd8#
