Correct answer: Be71...f:e6[a] 2.Q:f4#[A] 1...f6/[б]/ 2.B:f4#[Б] 1...Bh7 2.N:f7# 1...Bc7/Bd8/Ba5 2.R:c5# 1...f3 2.Qe4# 1...f:g6 2.N:g6# 1...f5 2.Qe2# 1.R