Correct answer: Qf11...Nb2[a]/Nb6/Nc3 2.R:c5#[Б] 1...Nf7/Nc6/[б]//Nb7 2.B:f7#[C] 1...Kc4/e4[c] 2.Qe4#[A] 1...c4[d] 2.Nc7#[D] 1.Qb1? (2.Qd3#) 1.
