Correct answer: Bf51...c3[a] 2.e:f4#[A] 1...g3/[б]//R:h2/[б]/ 2.e:d4#[Б] 1...Rh4/Rh5/Rh6/Rh7 2.e:d4#[Б]/e:f4#[A] 1...Rh8 2.e:d4#[Б]/e:f4#[A]/Q:h8# 1...Rg3/Rhf3 2.Qh8# 1..
