Correct answer: Bd61...Ne4[a] 2.Nf5#[A] 1...Be4/[б]/ 2.Nec2#[Б] 1...Nd1/Nb1/Nb5/Na2 2.Bc5# 1...Ne2 2.Bc5#/Nf5#[A] 1.Kf1? (2.Nf5#[A]/Ne
