Correct answer: Be71...Qc6[a]/Qe7[e] 2.Qf2#[A] 1...Qc5/[б]//Qc4[c]/Qc3[c]/Qc1[c]/Qh7/[б]//Qe5[g]/Qf4[g]/Q:g3[g]/Bg7 2.Qh7#[Б] 1...Qa7[d]/Qd6[
