Correct answer: Qa81...Rc4[a]/Rb5[a]/R:a5[a] 2.N:c4#[A] 1...Rc6/[б]//Rc7[c]/Rc8/[б]/ 2.d4#[Б] 1...Bg1/Bg3 2.Bg3# 1...Bf4+ 2.e:f4# 1.R:c5? (2.Nc4#[A]
