Correct answer: Bh71...Ne7[a]/Nf4[a]/Nf6[a]/Nc7[a]/Nb6[a] 2.Ba2#[A] 1...Bh7/[б]/ 2.Q:h7#[Б]/B:h7#[C] 1...N:c3 2.N:c3# 1.Qh7[Б]? zz 1...Ne7[a]/