Correct answer: Nb71...Kc4[a] 2.Qd3#[A] 1...Kc6/[б]/ 2.Qd7#[Б] 1.Ne4? zz 1...Kc4[a] 2.Nd6#[C] 1...Kc6/[б]/ 2.Nd4#[D] 1...Ka4[d] 2.Qd7#[Б] but 1...