Correct answer: N:f31...Be6[a]/Bf7/[б]//Bg8/[б]//Bc4[c]/Bb3[d]/Ba2[a] 2.d5#[A] 1...g2[e] 2.N:g2#[Б] 1...f2+[f] 2.Q:f2#[C] 1.Bg6[D]? zz 1...Be6[a]/Bf7/[б]//B