Correct answer: Ng51...Rd4[a] 2.Bd6#[A] 1...Ng7/Nd6/[б]//Nc7 2.Q:f6#[Б] 1...f5[c] 2.Qe7#[C] 1.Be3+?? 1...Rd5 2.R:d5# but 1...d5! 1.Bb6+?? 1...R<