Correct answer: Nc51...Ke3[a]/N:g3[c]/Ng7[c]/Nh4[c]/Nh6[c]/Ne7[e]/Nd6[c] 2.Bf2#[A] 1...Ke5/[б]//Ne3[d] 2.Bc3#[Б] 1.Kd8? zz 1...Ke3[a]/N:g3[c
