Correct answer: Bf21...Bh4[a] 2.g4#[A] 1...Rf3/[б]//Rf2/Rf1/R:f7/Re5/Rd5/Rc5/Rb5/Ra5 2.Bg6#[Б] 1.Kg3? (2.Qg4#) 1...Bh4+[a] 2.Q:h4#[C]