Correct answer: Rh51...Kd4/Ne1[a]/Nf2[a]/Nf4/[б]//Nc1[a]/Nb2[a]/Nb4[a] 2.Bb2#[A] 1.Kc4? zz 1...Ne1[a]/Nf2[a]/Nf4/[б]//Nc1[a]/Nb2+[a]/Nb