Correct answer: Kf71...Kh4[a] 2.Nf3#[A] 1.h3? zz 1...Kh4[a] 2.Qg4#[Б] 1...f:g5/[б]/ 2.Qh7#[C] but 1...Kh6[c]! 1.h4? zz 1...f:g5/[б]/ 2.Q:g5#[D] 1...Kh6[c] 2.Q<