Correct answer: Qa31...f3[a]/Nf3/[б]/ 2.Qf5#[A] 1...Ng2[c]/Nc2[c] 2.d3#[Б] 1...Nd3[d] 2.f3#[C] 1.K:g7? zz 1...Nf3/[б]/ 2.Qh7#[D] 1...Ng2[c]/Nc2[c] 2.d3#[Б]