Correct answer: Nd51...Nh8[a]/Nf8/[б]//Ne5/[б]//Ne7[c] 2.Ne5#[A] 1...Nd4[d]/Ne1[e]/Ne3[e]/Nb4[f]/Na1[e] 2.N:d4#[Б] 1...e5[g] 2.Bd7#[C] 1...Bc4[h]/B