Correct answer: Qh11...Ra7[a] 2.Q:a7#[A] 1...Ra8/[б]/ 2.Q:a8#[Б] 1...Ra6 2.Q:a6# 1.Qb8? zz 1...Ra7[a] 2.Q:a7#[A] 1...Ra8/[б]/ 2.Q:a8#[Б] but 1...R