Correct answer: Ba51...Ne2[a] 2.Ne3#[A] 1...Ng1/Ng5/Nh2/[б]//Nh4/Ne1/Ne5 2.Qe1#[Б] 1...Ne6/Nf5/Nc2/Nc6/Nb5 2.Q:f3# 1...Nd2 2.N