Correct answer: Qd61...Kc3[a] 2.Qb3#[A] 1...Ke3/[б]/ 2.Qf3#[Б] 1.Kc1?? zz 1...Kc3[a] 2.Qc4#/Qb3#[A] 1...Ke3/[б]/ 2.Qf3#[Б] but 1...Ke2! 1.Ke1?