Correct answer: Qa11...Kg4[a] 2.Qe4# 1.Qa7? zz 1...Kg4[a] 2.Qd4#[A] 1...g4/[б]/ 2.Qe7#[Б] but 1...f4! 1.Qa6? zz 1...Kg4[a] 2.Qc4#[C] 1...g4/[б]/ 2.Q