Correct answer: Qc51...d:c3[a] 2.Qd8#[A] 1...B:c3/[б]/ 2.Qf5#[Б] 1...e2 2.R:d2# 1.Qa7? (2.Q:d4#) 1...d:c3[a] 2.Qd7#[E] 1...B:c3/[б]/ 2.Qh7#[D] 1...K:c3[c] 2
