Correct answer: Q:h41...Ka4[a] 2.Qd7#[A] 1...Ka6/[б]/ 2.Qd3#[Б] 1.Qh6? zz 1...Ka4[a] 2.Qc6#[C] 1...Ka6/[б]/ 2.Nc7#[D] but 1...h3! 1.Qh5? zz 1...K