Correct answer: Bd41...Nd6[a]/Nd8/[б]//Na5/[б]/ 2.N:c5#[A] 1...Ng3[c]/Nf2[d] 2.Nf2#[Б] 1...f:e5 2.R:e5# 1.Bb3? zz 1...Nd6[a]/Nd8/[б]//Na5/[б]/ 2.N