Correct answer: Ng21...Kd4[a] 2.Qf4#[A] 1...d4/[б]/ 2.Nd3#[Б]/R:e6#[C] 1.Kg6? (2.Qe3#[D]) 1...Kd4[a] 2.Qf4#[A] 1...d4/[б]/ 2.Nd3#[Б] but 1...Nc2! 1.N
