Correct answer: Ba31...b1Q[a]/b1R[a]/b1B 2.Qd2#[A] 1...b1N/[б]/ 2.Ra2#[Б] 1...Rc3/R:b4/Rd4/Re4/Rf4/Rg4 2.R:c3# 1...R:c5 2.R:c5# 1.R