Correct answer: Qd71...Nh5[a]/Nf5[a]/Ne8[a] 2.Qg8#[Б] 1...Ne6/[б]//e4[c] 2.Qe4#[C] 1...Bc5/Bc7/Bb8 2.R:c5#[A] 1.Rc3?? (2.Qc4#) 1...Bc5 2.R
