Correct answer: Qf31...Bc6[a] 2.Ba3#[A] 1...Rc5/[б]/ 2.Re6#[Б] 1.Qd2? (2.Q:d5#) 1...Bc6[a] 2.Qb4#[C] 1...Rc5/[б]/ 2.Qh6#[D] but 1...d4! 1.Ba3+[A]??
