Correct answer: Nfd41...Rd4+[a] 2.Q:d4#[A] 1...e:f5/e5 2.Q:d5# 1.Nbd4[Б]? (2.Be2#/Bc2#) 1...R:d4+[a] 2.Q:d4#[A] 1...Rb5+/[б]/ 2.N:b5#[C] 1...Rc5 2.B