Correct answer: N:d41...b2[a] 2.Ra3#[A] 1...Bb2 2.Q:b2# 1...d:c4 2.R:c4# 1...Ng3/Nh2/Ne3/Nd2 2.Qd2# 1.Nb4? zz 1...b2[a] 2.Qc2#[C] 1...Ne6/[б]//