Correct answer: Re11...Nf2[a]/Nc3/[б]//Nb2[a] 2.Qe1#[Б] 1...Bd3[c]/Bd5[c]/Bc6[c]/Bb7[c]/Ba8[c] 2.R:d3#[C] 1...K:e3 2.Nb3# 1...f2 2.Re2# 1...N:e3
