Correct answer: Ne51...Bc5[a] 2.Bc7#[A] 1...Nd7/[б]/ 2.Rc6#[Б] 1...Ng3/Nh4/Nh6/Ne3/Nd4 2.Bc7#[A]/Qe5# 1.Rc4? (2.Bc7#[A]) but 1...Bc5[a]!